3x3 matrix with while loop
Mostrar comentarios más antiguos
Produce a random 3x3 matrix A that is invertible and display it. Hint: Use a while-loop until you get one with non-zero determinant. To create a random matrix with N rows and M columns,use the MATLAB command rand(N,M).
I know how to produce the 3x3 matrix and how to display it. I am just a little confused on how to use the while-loop. Can someone please help me?
2 comentarios
Alex Mcaulley
el 21 de En. de 2020
determinant = 0;
while determinant == 0
%Generate the random matrix
%Calculate the determinant of that matrix
end
Benjamin Trivers
el 21 de En. de 2020
Respuestas (1)
Jeremy
el 21 de En. de 2020
n = 3; m = 3;
A = zeros(n,m);
while det(A) == 0
A = rand(n,m);
end
4 comentarios
Benjamin Trivers
el 21 de En. de 2020
Jeremy
el 21 de En. de 2020
"Use a while-loop until you get one with non-zero determinant"
The problem asks for an invertible matrix, meaning that the inverse exists. You are looking for a determinant that is not equal to zero.
A zero determinant would not be an invertible matrix (i.e., the inverse does not exist because the determinant is zero).
Benjamin Trivers
el 21 de En. de 2020
Jeremy
el 21 de En. de 2020
Using rand, it's fairly unlikely that you'll create a matrix whose determinant is 0. It'd probably be easier to get a 0 determinant with randi
That being said, maybe running this will help you see what's going on
n = 3; m = 3;
A = zeros(n,m);
k = 0;
while det(A) == 0
A = rand(n,m);
k = k + 1;
fprintf(1,'\nIteration Number %i \n',k)
fprintf(1,' Matrix A = \n\n')
disp(A)
fprintf(1,'The Determinant of Matrix A is: \n')
disp(det(A))
end
And if you wanted an (approximately) zero determinant:
n = 3; m = 3;
A = eye(n,m);
k = 0;
while abs(det(A)) > 0.001
A = rand(n,m);
k = k + 1;
fprintf(1,'\nIteration Number %i \n',k)
fprintf(1,' Matrix A = \n\n')
disp(A)
fprintf(1,'The Determinant of Matrix A is: \n')
disp(det(A))
end
Using randi instead:
n = 3; m = 3;
A = eye(n,m);
k = 0;
while det(A) ~= 0
A = randi([0 10],n,m);
k = k + 1;
fprintf(1,'\nIteration Number %i \n',k)
fprintf(1,' Matrix A = \n\n')
disp(A)
fprintf(1,'The Determinant of Matrix A is: \n')
disp(det(A))
end
I hope this helps
Categorías
Más información sobre Logical en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!