Question on using interpolate function

1 visualización (últimos 30 días)
Deepa Maheshvare
Deepa Maheshvare el 28 de En. de 2020
Comentada: Deepa Maheshvare el 28 de En. de 2020
I've the following
x = [1 2 3 4 5 6];
data = [0.1 0.2 0.3 0.4 0.4 0.4];
vq1 = interp1(data,x,0.4)
I want to find the x value at which data has 0.4 (first occurence).
I used interpolate. But the following error occurS
The grid vectors must contain unique points.
Any suggestions on how to proceed when data doesn't contain uniqe values will be helpful
  1 comentario
Deepa Maheshvare
Deepa Maheshvare el 28 de En. de 2020
I'm still expecting answers for this post. Unfortunately, the following suggestions didn't help.

Iniciar sesión para comentar.

Respuestas (2)

KSSV
KSSV el 28 de En. de 2020
Use logical indexing:
x = [1 2 3 4 5 6];
data = [0.1 0.2 0.3 0.4 0.4 0.4];
vq1 = x(abs(data-0.4)<10^-5)
  1 comentario
Deepa Maheshvare
Deepa Maheshvare el 28 de En. de 2020
Editada: Deepa Maheshvare el 28 de En. de 2020
I'm looking for an interpolation function. It may happen that Ive to check for a value of 0.45 that is not present in data

Iniciar sesión para comentar.


Bhaskar R
Bhaskar R el 28 de En. de 2020
"I want to find the x value at which data has 0.4 (first occurence)."
match_loc = find(data == 0.4);
val = x(x == match_loc(1)); % first occurance of 0.4

Categorías

Más información sobre MATLAB en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by