How can i make array with strings ?
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Akshay Kumar
el 6 de Feb. de 2020
Respondida: Guillaume
el 6 de Feb. de 2020
I need to make a array with strings. For exmaple I have tried this.
for i =1:100
for j =1:200
D(i,j) = sprintf('z_prop(%d,%d,hbsigmci)=%.4f;',i,j,normrnd(0,1));
end
end
I am getting error in assignment. Provide solution to error or Alternate way.
Thaks.
2 comentarios
Rik
el 6 de Feb. de 2020
What do you want to with this? It looks like you are preparing something with eval, which I would strongly discourage.
Also, do you want the result to be of the string class or the char class?
Stephen23
el 6 de Feb. de 2020
Editada: Stephen23
el 6 de Feb. de 2020
This looks like the start of some slow, complex, obfscuated, buggy code:
'z_prop(%d,%d,hbsigmci)=%.4f;'
What are you planning on doing with that character vector? Why not just assign that value directly?:
z_prop(i,j,hbsigmci) = normrnd(0,1);
Respuesta aceptada
Guillaume
el 6 de Feb. de 2020
Note that strictly speaking you're not creating strings but char vectors. You may actually prefer generating strings which are easier to work with. If you want string simply replace the single quotes ' by double quotes " and you'll find that your code work exactly as you expected. However, you should preallocate the output array before the loop for efficiency:
D = strings(100, 200); %preallocate array
for j = 1:200
for i = 1:100
D(i, j) = sprintf("z_prop(%d,%d,hbsigmci)=%.4f;",i,j,normrnd(0,1));
end
end
If you want to work with char vectors, you need to store them in a cell array, not a matrix:
D = cell(100, 200);
for j = 1:200
for i = 1:100
D{i, j} = sprintf('z_prop(%d,%d,hbsigmci)=%.4f;',i,j,normrnd(0,1));
end
end
Note: another way to generate your output, which doesn't involve a loop
[r, c] = ndgrid(1:100, 1:200);
hbsigmci = normrnd(0, 1, size(r));
%for strings:
Dstring = reshape(compose("z_prop(%d,%d,hbsigmci)=%.4f;", r(:), c(:), hbsigmci(:)), size(r));
%for char vectors
Dchar = reshape(compose('z_prop(%d,%d,hbsigmci)=%.4f;', r(:), c(:), hbsigmci(:)), size(r));
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