Calling a function inside another function with iteration
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Jose Sosa Lopez
el 17 de Feb. de 2020
Editada: Jose Sosa Lopez
el 18 de Feb. de 2020
Hello community,
I am trying to reproduce a graph, but I guess I have a problem calling a function. Could you help me?
clear all; clc; close all;
c=1;
Yi0=c;
t=linspace(0,10,101);
T=0.1;
k=4;
for ite=2:101
y(ite)=funcion(T,t(ite),Yi(ite-1),k); %(Maybe here I have an error?)
end
plot(t,y')
%%
function Yout=funcion(T,t,Yi0,k)
Yi=zeros(k,1);
Yi(1)=Yi0;
for itek=2:k
for n=1:(k-1)
Yi(itek)=(T/(itek-1))*(Yi(itek-1)-exp(t(ite))*(Yi(n)*Yi(itek-n)));
Yi(itek)=Yi(itek)+Yi(itek-1); %I want to use in my next iteration, for Yi(1)= to the sum of the previous Yi(itek), so I dont know how o put it
end
end
Yout=sum(Yi);
end
the graph should be like this:
3 comentarios
Giuseppe Inghilterra
el 17 de Feb. de 2020
Hi,
in your code there are several errors. Example in following line:
y(ite)=funcion(T,t(ite),Yi(ite-1),k); %(Maybe here I have an error?)
you don't initialize Yi before, thus matlab returns an error.
In following line
Yi(itek)=(T/(itek-1))*(Yi(itek-1)-exp(t(ite))*(Yi(n)*Yi(itek-n)));
when you evaluate exp(t(ite)), the variable "ite" is not defined inside function. Maybe it should be "itek" instead.
In general I advice you to choose more appropriate name variables, in this way you are less error prone.
I finish to run code after these two errors.
Do you have mathematical formulation of the curve that you want to plot? It will be easier check your code.
Respuesta aceptada
Más respuestas (0)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!