How count positive numbers, but when you get a negative, the sum stops. so then, sum the following sequence of positive numbers..
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Example
v =
1 1 -1 1 1 1 -1 -1 1
%sum the sequence of positive numbers that are together
sol =
2 3 1
Regards Claudio
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Respuesta aceptada
Andrei Bobrov
el 13 de Oct. de 2012
Editada: Andrei Bobrov
el 13 de Oct. de 2012
v = [1 1 -1 1 1 1 -1 -1 1];
z = v > 0;
id = find([true;diff(v.') ~= 0]);
k = diff([id;numel(v)+1]);
out = k(z(id));
or use Image Processing Toolbox
v = [1 1 -1 1 1 1 -1 -1 1]
z = v > 0;
s = regionprops(z, 'Area');;
out = [s.Area];
or
v = [1 1 -1 1 1 1 -1 -1 1];
v1 = [-v(1)*sign(v(1)),v,-v(end)*sign(v(end))];
out = strfind(v1,[1, -1])-strfind(v1,[-1 1]);
1 comentario
Más respuestas (2)
Wayne King
el 13 de Oct. de 2012
Editada: Wayne King
el 13 de Oct. de 2012
x = randn(100,1);
sum(x(x>0))
For an example with integers:
x = randi([-5 5],20,1);
sum(x(x>0))
Walter Roberson
el 13 de Oct. de 2012
sum(x(1 : find(x <= 0, 1)))
or
sum(x .* cumprod(x > 0))
1 comentario
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