Borrar filtros
Borrar filtros

how to get an matrix as an output in a function

3 visualizaciones (últimos 30 días)
Faezeh Manesh
Faezeh Manesh el 23 de Feb. de 2020
Comentada: darova el 24 de Feb. de 2020
I have the following function I do not know why it is not working. Would you please help me?
function [L_e]=L_element(e,nnpe,nn)
% Gather matrix
L_e=zeros(nnpe,nn);
for i=1,nnpe
for j=1,nn
if j==(nnpe-1)*(e-1)+i
L_e(i,j)=1;
end
end
end
end

Respuesta aceptada

Rik
Rik el 23 de Feb. de 2020
Editada: Rik el 23 de Feb. de 2020
The mlint is giving you a hint: it wants you to put a semicolon to suppres output. Why would you have an output with the for loop? Because you put a comma instead of a colon:
function [L_e]=L_element(e,nnpe,nn)
% Gather matrix
L_e=zeros(nnpe,nn);
for i=1:nnpe
for j=1:nn
if j==(nnpe-1)*(e-1)+i
L_e(i,j)=1;
end
end
end
end
Of course you can also avoid the nested loop:
function [L_e]=L_element(e,nnpe,nn)
[I,J]=ndgrid(1:nnpe,1:nn);
L_e= J==(nnpe-1)*(e-1)+I ;
L_e=double(L_e);
end
  5 comentarios
Faezeh Manesh
Faezeh Manesh el 23 de Feb. de 2020
Thanks for your response it is working now.
darova
darova el 24 de Feb. de 2020
Don't accept the answer

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by