analytic solution with infinite sum

Hi,
I am having trouble figuring out how to write the code for this function that contains an infinite series.
Ti = 150;
T1 = 300;
T2 = 200;
L = 1;
alpha = 0.1;
delta_x = 0.05;
delta_t = 0.01;
N_time = 51;
N_space = 21;
x = linspace(0,L,N_space);
t = linspace(0,0.5,N_time);
I need to make the code so that it can compute this:
% I also need a little help in making the function. I have used syms m x t, but it doesn't work all the time.
c_m = (2/m*pi) ((Ti - T1)-(-1)^m*(Ti - T2))
T(x,t) = T1 + (T2 - T1)*(x/L) + %my unknown part: the infinite sum starting from 1 of c_n*exp(-m^2*pi^2*alpha*t/L^2)*sin(m*pi*x/L)

3 comentarios

Walter Roberson
Walter Roberson el 23 de Feb. de 2020
The only function that MATLAB has for working with infinite sums to create an analytic solution, is symsum() from the Symbolic Toolbox.
darova
darova el 23 de Feb. de 2020
Can you please write formula in LaTeX format?
Something like this:
Chien-Cheng Chiu
Chien-Cheng Chiu el 23 de Feb. de 2020

Iniciar sesión para comentar.

Respuestas (1)

darova
darova el 23 de Feb. de 2020
Here is my attempt
Ti = 150;
T1 = 300;
T2 = 200;
L = 1;
alpha = 0.1;
delta_x = 0.05;
delta_t = 0.01;
N_time = 51;
N_space = 21;
x = linspace(0,L,N_space);
t = linspace(0,0.5,N_time);
[X,T] = meshgrid(x,t);
cm = X*0;
for m = 1:100
C1 = 2/m/pi*( (Ti-T1)-(-1)^m*(Ti-T2) );
C2 = exp(-m^2*pi^2*alpha*T/L^2).*sin(m*pi*X/L);
cm = cm + C1*C2;
end
surf(X,T,cm)
xlabel('X')
ylabel('T')

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el 23 de Feb. de 2020

Respondida:

el 23 de Feb. de 2020

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