Easier method to iterative matrix multiplication?

    n = 10
    matrix = zeros(n,n);
    matrix(1,1:n) = 2 
    matrix1 = zeros(n,n);
    matrix1(1:n,1) = 4
    
    for i = (1:n)
        matrix(i+1,1:n) = matrix(i,1:n)*matrix1;   
    end
    matrix
   

Outputs:

matrix =

     2     2     2     2     2     2     2     2     2     2
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0


matrix1 =

     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
    
 matrix =

           2           2           2           2           2           2           2           2           2           2
          80           0           0           0           0           0           0           0           0           0
         320           0           0           0           0           0           0           0           0           0
        1280           0           0           0           0           0           0           0           0           0
        5120           0           0           0           0           0           0           0           0           0
       20480           0           0           0           0           0           0           0           0           0
       81920           0           0           0           0           0           0           0           0           0
      327680           0           0           0           0           0           0           0           0           0
     1310720           0           0           0           0           0           0           0           0           0
     5242880           0           0           0           0           0           0           0           0           0
    20971520           0           0           0           0           0           0           0           0           0

The point is that matrix will have more values added to it. matrix 1 will be filled with many different values. I'm trying to find an easier way than a for loop.

matrix1 is made to be that way for easier explanation

[Bjorn Gustavsson]

Looks a bit strange. matrix(i+1,1:n) will be an [1 x n] array, on the right-hand-side matrix(i,1:n) will have the same size. That will force matrix1 to be a scalar for matrix-multiplication to work. Perhaps you want elementwise multiplication? Or some slightly different operation?

[arthurk]

Apologies, terrible question. I will explain it better

Answer 1

[Matt J]

No, a loop is the best way.