Plot interval for inverse cos

1 visualización (últimos 30 días)
Orennia Goetzinger
Orennia Goetzinger el 5 de Mzo. de 2020
Comentada: Orennia Goetzinger el 5 de Mzo. de 2020
I'm trying to plot a ratio that's periodic, so every 2pi radians, the function value should be one. The plot I'm getting shows a value much closer to zero however, so I assume I need to adjust the interval I'm plotting over, but I'm not sure how to do that or what the proper interval would be. What's the right way to approach integer values of 2pi such that my plot is accuracte and the function value is one at these places?
The plot I'm getting looks like this:
And it should look like this:
x=linspace(0,5*pi)
y3=(1-0.5)^2./(1+0.5^2-2*0.5*cos(x))
y4=(1-0.9)^2./(1+0.9^2-2*0.9*cos(x))
y6=(1-0.99)^2./(1+0.99^2-2*0.99*cos(x))
plot(x,y3,x,y4,x,y6)

Respuesta aceptada

the cyclist
the cyclist el 5 de Mzo. de 2020
Instead of the default value, increase the number of points used in linspace. For example,
x=linspace(0,5*pi,1000)

Más respuestas (0)

Categorías

Más información sobre 2-D and 3-D Plots en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by