elements of array are odd or even

clear all
clc
a=round(0+9*rand(10,1));
for n=a
    if mod(n,2)==0
        disp(n),disp('is even')
    elseif n==0  
       disp(n),disp('is 0')
    else
       disp(n),disp('is odd')
    end
end

the program must check which of the numbers of array are even or odd?but it doesnt work correctly...

Answer 1

[Sriram Tadavarty]

Hi Pooneh,

The following updates will perform what is looked for

clear all
clc
a=round(0+9*rand(10,1));
for n=1:length(a) % For loop from 1 to length(a), then access each element of a with n, display n
    if mod(a(n),2)==0 
        disp(num2str(n) + " is even")
    elseif n==0  
       disp(num2str(n) + " is 0")
    else
       disp(num2str(n) + " is odd")
    end
end

Hope this helps.

Regards,

Sriram

[pooneh shabdini]

Hi:) Thank you...but Do you know why my way doesn't work?

[Sriram Tadavarty]

I can help you understand your code. In your code, you have placed the loop for n = a, here is a is a vector, which implies n is the complete vector but not the single element of the vector. As this is vector that is passed in to the conditions, there is not case satisfied this, going with the else statement. There by not giving what you expected.

So, the modification is made to loop it across each element in the code.

Hope this helps. Regards, Sriram

Answer 2

[pooneh shabdini]

Thanks again But I've read we can use a vector in this way in for loop....

[Sriram Tadavarty]

Yes, you could use. It depends on the purpose of what you intended to do.

[pooneh shabdini]

Thank you?