I need to evaluate the function in each combination of (x1, x2, x3), that is:
for i=1:11
for j=1:11
for k=1:11
z(i,j,k)=feval(f,x1(i),x2(j),x3(k));
end
end
end
This evaluation gives us an NxNxN matrix (cell?). I don't know what it's called hahahaha
[sfx, ind]=sort(z(:));
we selected the t smallest function values
sfx=sfx(1:t);
And the indexes corresponding to the t smallest function values
ind=ind(1:t);
Does anyone have any idea how I can return the values of x1, x2 and x3 corresponding to these t smallest function values?

4 comentarios

Rik
Rik el 27 de Mzo. de 2020
This time I edited your question for you. Next time, please use the tools explained on this page to make your question more readable.
Everton Silva
Everton Silva el 27 de Mzo. de 2020
Thanks for your suggest. It's my first time that I asked here, the next time I'll write in this right way. ;-)
Guillaume
Guillaume el 27 de Mzo. de 2020
Notes:
z(i,j,k)=feval(f,x1(i),x2(j),x3(k));
can be written more simply as
z(i,j,k)=f(x1(i),x2(j),x3(k));
assuming that f is a function handle.
Also, depending on f you may not need the loops at all.
Steven Lord
Steven Lord el 27 de Mzo. de 2020
To compute the smallest values you can use the mink function.

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Rik
Rik el 27 de Mzo. de 2020
Editada: Rik el 28 de Mzo. de 2020

1 voto

The indices you get in your last operation can be converted to subscripts, which will correspond to your three inputs.
ind=ind(1:t);
[x1_ind,x2_ind,x3_ind]=ind2sub(size(z),ind);
x1=x1(x1_ind);
x2=x1(x2_ind);
x3=x1(x3_ind);

4 comentarios

Everton Silva
Everton Silva el 27 de Mzo. de 2020
When I write this commands it's doesn't work. Appears this message: ''Error using sub2ind
Too many output arguments.''
Walter Roberson
Walter Roberson el 27 de Mzo. de 2020
[x1_ind,x2_ind,x3_ind]=ind2sub(size(z),ind);
Everton Silva
Everton Silva el 27 de Mzo. de 2020
Thank you so much.
Rik
Rik el 28 de Mzo. de 2020
@Walter thanks for catching the mistake
@Everton you're welcome

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Más respuestas (1)

Torsten
Torsten el 27 de Mzo. de 2020
Editada: Torsten el 27 de Mzo. de 2020

0 votos

[X1,X2,X3]=ndgrid(x1,x2,x3);
Z=f(X1,X2,X3); %assumes f is vectorized
M=[X1,X2,X3,Z];
[~,idx]=sort(M(:,4));
sortedM=M(idx,:);
X1s=sortedM(1:s,1);
X2s=sortedM(1:s,2);
X3s=sortedM(1:s,3);

1 comentario

Everton Silva
Everton Silva el 27 de Mzo. de 2020
For example, if I write in the command window
t=11;
f=@(x1,x2,x3)(x1+x2+x3);
x1=0:0.1:1;
x2=0:0.1:1;
x3=0:0.1:1;
[X1,X2,X3]=ndgrid(x1,x2,x3);
Z=f(X1,X2,X3);
M=[X1,X2,X3,Z];
[~,idx]=sort(M(:,4));
sortedM=M(idx,:);
X1s=sortedM(1:t,1);
X2s=sortedM(1:t,2);
X3s=sortedM(1:t,3);
X=[X1s,X2s,X1s]
returns
X=
0 0 0
0.1000 0.1000 0.1000
0.2000 0.2000 0.2000
0.3000 0.3000 0.3000
0.4000 0.4000 0.4000
0.5000 0.5000 0.5000
0.6000 0.6000 0.6000
0.7000 0.7000 0.7000
0.8000 0.8000 0.8000
0.9000 0.9000 0.9000
1.0000 1.0000 1.0000

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el 27 de Mzo. de 2020

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Rik
el 28 de Mzo. de 2020

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