How to find maximum of a multivariable function using max()
8 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
enter
el 29 de Mzo. de 2020
Comentada: Ameer Hamza
el 30 de Mzo. de 2020
How to find maximum of a multivariable function using max(). Let's denote z = (y+cos(y))/(x^2) for x,y belonging to [1,15].
Respuesta aceptada
Ameer Hamza
el 29 de Mzo. de 2020
Editada: Ameer Hamza
el 30 de Mzo. de 2020
You can use fmincon function to find maximum value
z = @(x,y) (y+cos(y))./(x.^2);
sol = fmincon(@(x) -z(x(1),x(2)), 10*rand(2,1), [], [], [], [], [1;1], [15;15]);
x_sol = sol(1);
y_sol = sol(2);
4 comentarios
Ameer Hamza
el 30 de Mzo. de 2020
Michal, this is the limitation of the numerical optimization algorithm. They are sensitive to the initial guess. I found that for your objective function, 'interior-point' algorithm gives consistent results.
z = @(x,y) (y+cos(y))./(x.^2);
opts = optimoptions('fmincon', 'Algorithm', 'interior-point');
sol = fmincon(@(x) -z(x(1),x(2)), rand(1,2), [], [], [], [], [1;1], [15;15], [], opts);
x_sol = sol(1);
y_sol = sol(2);
Más respuestas (0)
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!