Why do we transfer the image into double?

3 visualizaciones (últimos 30 días)
Muhamed Sewidan
Muhamed Sewidan el 5 de Abr. de 2020
Comentada: Paul Hoffrichter el 4 de Dic. de 2020
I saw a lot of image processing examples and before conducting any analysis the image is transfered into double. Is it essential? and what is the benefit from doing so?

Respuesta aceptada

Image Analyst
Image Analyst el 5 de Abr. de 2020
No, it's usually not. But sometimes it is, like if you want to use conv2(). It has to do with how MATLAB likes to multiply variables of different classes.
  2 comentarios
Muhamed Sewidan
Muhamed Sewidan el 5 de Abr. de 2020
Could you please give me some cases in which I should transfer the image into double before carrying out any processes?
Image Analyst
Image Analyst el 5 de Abr. de 2020
Other than conv2(), I can't think of any off the top of my head. But you obviously must have had some cases in mind because you're the one who brought up the question. Care to share those cases?

Iniciar sesión para comentar.

Más respuestas (1)

Paul Hoffrichter
Paul Hoffrichter el 4 de Dic. de 2020
MATLAB when using mixed mode arithmetic, will try to save memory.
250 + 10 = 260, right?
>> x =double(250) + uint8(10);
>> x
x =
uint8
255
In other languages, like C/C++, the rule is to maximize precision. Avoid mixed mode arithmetic unless you need it. There is no error or warning provided, by default, in the above code.
  4 comentarios
Muhamed Sewidan
Muhamed Sewidan el 4 de Dic. de 2020
thank you
Paul Hoffrichter
Paul Hoffrichter el 4 de Dic. de 2020
Glad to help.

Iniciar sesión para comentar.

Categorías

Más información sobre Images en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by