Function handle with inputs

% When I input W(3) IN THE COMMAND LINE (without any input for ii), there is an output for W?
% Why is that?

m = 3;
L = 10;
R = 1;
r = R/(m+1);
S = sqrt(2);
s = S/(m+1);
d1 = 1;
d2 = 0.25;
gama = atan(R/d1);

phi_i = @(ii, m) atan( (d1 + (ii*d2)./(m+1))./(r/3) );
W = @(m) ( r + s*sum(sin(gama + pi/2 - phi_i(1:m, m))) );

Answer 1

[Mehmed Saad]

You input phi_i in function W as follow

ii = 1:m;
m  = m;

Now you feed input W function a value (m), suppose 3

the function phi_i gets following

phi_i(1:3,3)

So that's why you will get value when executing W(3)

On the other hand

This will not give you output until you provide ii value in your workspace

W = @(m) ( r + s*sum(sin(gama + pi/2 - phi_i(ii, m))) );