RGB Color Space Image Segmentation

Hello All.
I have been trying to replace the original R, G and B components of an RGB image by applying the attached equations in MATLAB.
I don't know the functions to use. I have tried applying different filters but the results I get are inaccurate.

8 comentarios

There is nothing attached so we don't know the functions to use either. In the meantime, here's a snippet that might get you started:
% Extract the individual red, green, and blue color channels.
redChannel = rgbImage(:, :, 1);
greenChannel = rgbImage(:, :, 2);
blueChannel = rgbImage(:, :, 3);
% Now do your math on the separate channels, then...
% Recombine separate color channels into a single, true color RGB image.
rgbImage = cat(3, redChannel, greenChannel, blueChannel);
Muftahu Kabir
Muftahu Kabir el 14 de Abr. de 2020
Thank you for the code. Please find attached the equations
Muftahu Kabir
Muftahu Kabir el 15 de Abr. de 2020
I have splitted the image into the three channels. But I don't know the function to use in doing some maths on the channels before using "cat()" to combine all my calculations into a single image
Image Analyst
Image Analyst el 15 de Abr. de 2020
The equations say to set all pixel values to (0,0,0) which is the RGB for pure black. They'll never eve get (255,255,255) because I'' is never anything but (0,0,0) as you can see from equation (5). I think these equations were written down incorrectly. It does not do segmentation when you simply set everything to zero.
Muftahu Kabir
Muftahu Kabir el 22 de Abr. de 2020
Anyone please? Am still yet to resolve it. My main problem is "What function to use in mixing the individual channels using any combination (equation) of my choice".
Image Analyst
Image Analyst el 22 de Abr. de 2020
Everything is zero except I hat if I hat if I'' is more than 0. But from equation (5), I'' is never anything but zero. Hence I hat will never be anything but zero either. I suggest you contact the author for the correct formulas, or look into imgradient().
Mrutyunjaya Hiremath
Mrutyunjaya Hiremath el 24 de Abr. de 2020
There is a problem in given equations
Here is the reults, after some assumptions for intitial values, like Idash ... sigma ...
Muftahu Kabir
Muftahu Kabir el 24 de Abr. de 2020
Editada: Muftahu Kabir el 24 de Abr. de 2020
@Mrutyunjaya Hiremath
Interesting.... After using which of the equations did you arrive at your result? I have been trying to get a similar result to yours using equation (4) but I couldn't. Can you please share the code you used?

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Mrutyunjaya Hiremath
Mrutyunjaya Hiremath el 25 de Abr. de 2020
Hello Muftahu Kabir,
Here is the code ...
clear all;
close all;
clc;
I = imread('1.jpg');
figure, imshow(I);
IR = I(:,:,1);
IG = I(:,:,2);
IB = I(:,:,3);
I4 = I;
I41Index = find((IG - ((IR+IB)/2) + 15) > 0);
I4(I41Index) = 0;
I42Index = find((IR - IB) > 20);
I4(I42Index) = 0;
I43Index = find((IG - IR) > 15);
I4(I43Index) = 0;
figure, imshow(I4);
I5 = I4;
delta = 50;
I51Index = find(I4 > (255 - delta));
I5(I51Index) = 0;
I52Index = find(I4 < delta);
I5(I52Index) = 0;
figure, imshow(I5);
I6 = I5;
I61Index = find(I5 > 0);
I6(I61Index) = 255;
I62Index = find(I5 == 0);
I6(I62Index) = 0;
figure, imshow(I6);
imwrite(I6, 'I6.jpg');

1 comentario

Muftahu Kabir
Muftahu Kabir el 4 de Jun. de 2020
Hello Mrutyunjaya Hiremath,
I truly appreciate your contribution.
It has gone a long way assisting me in doing my research. Thank you so much

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