Error using findpeaks Expected Y to be a vector.

%Parameters
% Read in audio file
[y,Fs] = audioread('Happy Birthday Lower.wav');	
info = audioinfo('Happy Birthday Lower.wav');
sound(y,Fs) % Play the sound

% plot the data 
% Create a time component using info
t = 0:seconds(1/Fs):seconds(info.Duration); 
t = t(1:end-1);

figure(1)
plot(t,y)
xlabel('Time (s)')
ylabel('Audio Signal')

% Detect peaks from y
[pk_Fs, locs_Fs] = findpeaks(y,Fs, 'MinPeakDistance',0.03, 'MinPeakHeight',0.01);

I used this code to try and find the peaks of the given audio signal, the audio signal is extremly simple with no overlapping audio. But this error comes up:

Error using findpeaks

Expected Y to be a vector.

Error in findpeaks>parse_inputs (line 199)

validateattributes(Yin,{'double','single'},{'nonempty','real','vector'},...

Error in findpeaks (line 136)

= parse_inputs(isInMATLAB,Yin,varargin{:});

Error in SeperatePeaks (line 19)

[pk_Fs, locs_Fs] = findpeaks(y,Fs, 'MinPeakDistance',0.03, 'MinPeakHeight',0.01);

Answer 1

[Image Analyst]

y is probably stereo, so it's a 2-by-N matrix. Try extracting just one channel:

oneChannel = y(1, :);  % Or y(:, 1) depending on the shape of y
[pk_Fs, locs_Fs] = findpeaks(oneChannel, Fs, 'MinPeakDistance',0.03, 'MinPeakHeight',0.01);

[Saeeid Khalili]

it worked thank you!

[cezayir]

thank you

Answer 2

[Star Strider]

The findpeaks function only operates on vectors, and ‘y’ is apparently a (Nx2) matrix.

Try this:

for k =1:size(y,2)
    [pk_Fs{k}, locs_Fs{k}] = findpeaks(y(:,k),Fs, 'MinPeakDistance',0.03, 'MinPeakHeight',0.01);
end

That should work. (It generalises in the even that ‘y’ is a vector, as occasionally occurs.)

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