Deleting Row and Column

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Imani DaSilva
Imani DaSilva el 24 de Abr. de 2020
Editada: Imani DaSilva el 25 de Abr. de 2020
I am doing a project with matrices. I want to change the size of the matrix by deleting the last 2 rows and the last 2 column. I want to go from 0.01 to 0.15 in steps of 0.01. When I display Q1 I am able to delete the last 2 columns but the the last 2 rows and then when I try to delete the rows (disp Q2) it deleted the rows but not the columns. I want BOTH the last two ROW AND last two COLUMN to be deleted from the Matrix P. Any help is appreciated!!!!
P = [0.1 0.75 0 0 0.15 0; 0 0.1 0.8 0 0.10 0; 0 0 0.15 0.75 0.1 0; 0 0 0 0.1 0.1 0.8; 0 0 0 0 1 0; 0 0 0 0 0 1];
disp(P)
for v = 0.01:0.01:0.15
P(1,1) = v + P(1,1);
%disp(P)
Q1 = ([:,1 2 3 4]);
disp(Q1)
Q2 = P([1 2 3 4],:);
%Q2 = P(:, [5 6]);
disp(P)
end

Respuestas (2)

KSSV
KSSV el 24 de Abr. de 2020
If A is your matrix, you can remove last two rows and columns using:
[m,n] = size(A) ;
A(m-1:m,:) = [] ; % removes last two rows
A(:,n-1:n) = [] ; % removes last two columns
  2 comentarios
Imani DaSilva
Imani DaSilva el 24 de Abr. de 2020
when I try this method i am getting an error saying "Index in position 1 is invalid. Array indices must be positive integers or logical values." it prints out the first matrix correctly and then runs into that error.
KSSV
KSSV el 24 de Abr. de 2020
Show us the code which you have tried.

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James Tursa
James Tursa el 24 de Abr. de 2020
Q = P(1:end-2,1:end-2);
  3 comentarios
Imani DaSilva
Imani DaSilva el 24 de Abr. de 2020
from what i understand P(1:end-2,1:end-2) is for the subtracting the last two rows and colums starting from column 1 and row 1. So if i wanted to get the last 2 columns without the last 2 rows. I tried the same concept with removing the last 2 rows but extracting the last 2 columns and it is just giving me a vector of 1's. But i would want
0.1500 0
0.1000 0
0.1000 0
0.1000 0.8000
(1.0000 0) ->minus this row
(0 1.0000) -> minus this row
Imani DaSilva
Imani DaSilva el 24 de Abr. de 2020
I figured it out! thanks for the help

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