HOW TO STRİNG TO CHAR

how do I print this expression''110 011101110001111001111010 1111000001000100011011000111010'' in a matrix of 10x10?

Answer 1

[Image Analyst]

You can't. It's only 58 characters long - 60 if you include the spaces:

expression = "1100111011100011110011110101111000001000100011011000111010"
length(expression)
length(char(expression))

expression =

"1100111011100011110011110101111000001000100011011000111010"

ans =

1

ans =

58

In the meantime, try

expression = "1100111011100011110011110101111000001000100011011000111010"
length(expression)
charVector = char(expression)
length(charVector)
charMatrix = reshape(charVector, 2, 29) % or 10 by 10

[Gökhan BAYKARA]

ı wanna do QR kode with expression and 10*10 with space

[Image Analyst]

expression = "11 0011101110001111001111010 111100000 1000100011011000 11101011 001111010111 1000001000 1000110110 00111010"
% Get rid of spaces
expression = erase(expression, ' ')
% Change from string to character vector.
charVector = char(expression) % 100 characters long now
charMatrix = reshape(charVector, 10, 10)

expression =

"11 0011101110001111001111010 111100000 1000100011011000 11101011 001111010111 1000001000 1000110110 00111010"

expression =

"1100111011100011110011110101111000001000100011011000111010110011110101111000001000100011011000111010"

charVector =

'1100111011100011110011110101111000001000100011011000111010110011110101111000001000100011011000111010'

charMatrix =

10×10 char array

'1111100101'

'1010000100'

'0010011110'

'0010011000'

'1100111001'

'1110101001'

'1101010011'

'0110101010'

'1010110101'

'1010011010'

[Gökhan BAYKARA]

n your result vector, your value of 1 for the name length and 10 for the number will be fixed and will not change. But everyone's name is different because it is long; BINARY will be stored in the 5-bit data of the vector since SAHIN in the sample name has 5 values The total length in the format will be 5x (1 + 5 + 10) = 80 characters. Occupation in total, considering your name to be up to 9 characters Since the number of characters you can get is 5 * (1 + 9 + 10) = 100, in the 10x10 matrix, 0 * for your 0 values ​​in your result vector, 1 You can create your QR code to print '' (space) for its values. NOTE: Since 80 characters are occupied for the name given in the example, the remaining places in the matrix are blank "*" will be printed. QR code for the sample given:

[Image Analyst]

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Answer 2

[Gökhan BAYKARA]

n your result vector, your value of 1 for the name length and 10 for the number will be fixed and will not change. But everyone's name is different because it is long; BINARY will be stored in the 5-bit data of the vector since SAHIN in the sample name has 5 values The total length in the format will be 5x (1 + 5 + 10) = 80 characters. Occupation in total, considering your name to be up to 9 characters Since the number of characters you can get is 5 * (1 + 9 + 10) = 100, in the 10x10 matrix, 0 * for your 0 values ​​in your result vector, 1 You can create your QR code to print '' (space) for its values. NOTE: Since 80 characters are occupied for the name given in the example, the remaining places in the matrix are blank "*" will be printed. QR code for the sample given: