Heat Transfer Interations with while loops

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Javen Harris
Javen Harris el 4 de Mayo de 2020
I've been working on this code for the past couple days. I'm tyring to get the interations to run and get a time for how long it will take for T(1,p) to get to 200 degrees. Everytime I run the code to that, it runs for more than 10 minutes.
%%
%Steady Temperature at each node
clc
clear
L=.25; h=4000; Tinf=40; den=7850;
Cp=650;k=27.3; dx=5E-3;
diff=k/(den*Cp); Bi=(h*dx)/k;
Fo=(1/2)/(1+Bi);
dt_i=(Fo*dx^2)/diff;dt=1.3;
Ti=1200;
Ts=Tinf;
T_goal=200;
for i=1:51
x=(i-1)*dx;
T(i,1)=Ti;
end
nodes=1:51;
table=[nodes; T'];
fprintf('Node Initial Temperature\n')
fprintf(' %i %5.3f\n',table);
%%
p=1;
while T_goal<T(1,p)
p=p+1;
t=dt*(p-1);
for i=1:51
%for Cp
if 900<=T(i,p-1)
Cp=650;
elseif 745<=T(i,p-1)
Cp=545+(17820/(T(i,p-1)-731));
elseif 600<=T(i,p-1)
Cp=666+(13002/(738-T(i,p-1)));
else 20<=T(i,p-1)
Cp=(425+7.73*10^-1*T(i,p-1))-(1.69*(10^-3)*(T(i,p-1)^2))+(2.22*(10^-6)*(T(i,p-1)^3));
end
%For k
if 800<=T(i,p-1)
k=27.3;
else T(i,p-1)
k=54-3.33*(10^-2)*T(i,p-1);
end
diff=k/(den*Cp);
Bi=h*L/k;
Fo=(diff*dt)/L^2;
if i==1
T(i,p)= Fo*(2*T(i+1,p-1))+(1-2*Fo)*T(i,p-1);
elseif i==51
T(i,p)=2*Fo*(T(i-1,p-1)+Bi*Tinf)+(1-2*Fo-2*Bi*Fo)*T(i,p-1);
else
T(i,p)=Fo*(T(i-1,p-1)+T(i+1,p-1))+(1-2*Fo)*T(i,p-1);
end
end
end
T_i=T';

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