How do I plot intersection point of a function and y axis in matlab

Sketch the graph of the function y = f(x) and the y-axis onto the same figure. What is the meaning of the point of intersection? Apply the Secant method to solve f(x) = 0 accurate to within 10^(-3) for the equation

A) f(x) = e^x + 2^(-x) + 2 cos(x) ) 6 for 1 ≤ x ≤ 2.

clc;
clear;

x=[1 2];
y=exp(x)+power(2,(-x))+2*cos(x)-6;
plot(x,y)

%Secant method;
f=@(x) exp(x)+power(2,(-x))+2*cos(x)-6;
x0=1;
x1=2;
epsilon=0.001;
err=abs(x1-x0);
if f(x0)*f(x1)>0
    disp('enter valid interval!!!')
else
    while err>epsilon
        x2=(x0*f(x1)-x1*f(x0))/(f(x1)-f(x0));
        x0=x1;
        x1=x2;
        err=abs(x1-x0);
        root=x2;
    end
fprintf('\n The root is %4.3f ',root)
end

I can solve the secant method part but I can't plot the intersection point of the function and y-axis.

I would appreciate if you can tell me or show me how can I plot?

[Walter Roberson]

The interesection point of the function and the y axis is just the point at which the function equals 0. You can plot a marker there or a line such as with xline()