48 Dimensional Euclidean Distance.
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Hi Guys, Hopefully this will be a quicky. If I have two points in two dimensional space I find the distance as:
sqrt((x1-x2)^2 + (y1-y2)^2)
This is all good and well, but if I want the distance when each point has 48 (or otherwise) coordinates I don't really want to type out that equation. So is there some MatLab function which will let me pass it two arrays and find the resultant distance?
Thanks in advance,
Tim.
Respuesta aceptada
Jan
el 8 de Nov. de 2012
Editada: Jan
el 8 de Nov. de 2012
Most of all the components should not be stored in x1, y1, z1, ... but is vectors x1=[1 x 48], x2=[1 x48]. Then some alternatives:
x1 = rand(1, 48);
x2 = rand(1, 48);
x12 = x2 - x1;
Dist1 = sqrt(sum(x12 .^ 2))
Dist2 = sqrt(x12 * x12.') % DOT product calculates the sum internally
Dist3 = norm(x12)
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