Cell array....searching without a loop?

1 visualización (últimos 30 días)
jenka
jenka el 10 de Nov. de 2012
I have a cell array A. Size is 200x1. The size of A{1} is 501x201x119=i x j x k. The same is true for other cells in A. Now for each point in dimension i that goes from 1 to 501, I need to extract appropriate point from each cell, and find 90 percentile of these points and save it into 501x201x119 array. Could you please help if you have elegant solution to this problem.
EDITED By Matt Fig to add (from an 'Answer' by jenka):
Let me make it more clear. Let's say, per Matt, suggestion
A = {rand(5,3,2);rand(5,3,2);rand(5,3,2);rand(5,3,2)};
Sorry I do not have a excess to matlab right now so this is pseudo code:
for j=1:3
for k=1:2
B = [];
for i=1:5
B = cat(A{:}(i,j,k), B, 1); %not sure if we can do something like this
end
per_90_mat(i,j,k) = prcntile(B,90);
end
end
  4 comentarios
jenka
jenka el 10 de Nov. de 2012
Hi Azzi, I just replied below. Thank you!
Jan
Jan el 10 de Nov. de 2012
Do you mean cat(1, ...)? What should A{:}(i,j,k) do? It is no valid Matlan syntax.

Iniciar sesión para comentar.

Respuestas (1)

Matt Fig
Matt Fig el 10 de Nov. de 2012
Editada: Matt Fig el 10 de Nov. de 2012
Post a simple, small example of the FOR loop you have been using to solve the problem. Say
A = {rand(5,3,2);rand(5,3,2);rand(5,3,2);rand(5,3,2)};
Now what are you doing with A?
EDIT
O.k., so it looks like you want to do something like this without the loops:
I = 5;
J = 3;
K = 2;
A = {randi(10,I,J,K);randi(10,I,J,K);randi(10,I,J,K)};
for jj=1:J
for kk=1:K
for ii=1:I
B = cellfun(@(x) x(ii,jj,kk),A);
per_90_mat(ii,jj,kk) = prctile(B,90);
end
end
end
You can do the same thing like this:
per_90_mat2 = prctile(cat(4,A{:}),90,4)

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by