How can i solve this?
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Arturzzaman Rustam
el 27 de Mayo de 2020
Comentada: David Hill
el 27 de Mayo de 2020
For a given rectangular matrix A, it is required to find the number of elements that exceed in absolute value the arithmetic mean of all elements of this matrix.
A=rand(3,4)
M=mean(mean(A))
A(:)
x=abs(M)
c=0
fori = length(ans)
if (ans(i)>abs(x))
c=c+1
end;
i did this. Is this even the solution of that question?im new to matlab
0 comentarios
Respuesta aceptada
David Hill
el 27 de Mayo de 2020
a=mean(abs(A),'all');
s=sum(A>a,'all');
2 comentarios
David Hill
el 27 de Mayo de 2020
Sorry, I misunderstood you. You want to take the mean first, then abs. Here is a one-liner that will work for you.
s=nnz(A>abs(mean(A,'all')));
Más respuestas (0)
Ver también
Categorías
Más información sobre Matrices and Arrays en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!