Finding the numbers of a vector with the same length?
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Dear all
Assuming there is a vector consisting only 0 and 1 like:
x=[0 1 1 0 1 0 0 1 1 1 0 1 0 1 1 1 0 1 1 0 1 1 0 1]
I want to figure out how many times 1 or 1 1 or 1 1 1 or even longer 1 in a row exists are in this vector?
The solution here would be:
nr_1= 3
nr_1_1= 3
nr_1_1_1= 2
nr_1_1_1_1 = 0
....
Is there a easy way to do it?
Thanks for your help
(Matlab 2010a)
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Respuesta aceptada
C.J. Harris
el 14 de Nov. de 2012
rep=diff(find(diff([-Inf x Inf])));
val=x(cumsum(rep));
out = hist(rep(val == 1), max(rep));
2 comentarios
C.J. Harris
el 15 de Nov. de 2012
You can process the out data if you want to remove the zeros, for example:
[out(find(out ~= 0)); find(out ~= 0)]
This will then show occurrences (top row) and sequence length (bottom row).
Más respuestas (2)
Harshit
el 14 de Nov. de 2012
Hi,
You can save zero as it is and whenever 1 appears start a counter and count the number of 1s in succession. It is Run length encoding. When done just count the number of times the numbers appears.
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