Sorting matrix with specifications for the order

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Jean
Jean el 19 de Nov. de 2012
Hi,
I have a certain matrix with n rows and 3 columns. I want to sort it according to the sums of the squares of its columns.
For example, let's say my matrix is
0 0 1
0 0 2
1 1 1
Since for the second row we have: 0^2+0^2+2^2 = 4, which is larger than the 3rd row: 1^2+1^2+1^2 = 3. In such a case, I want my matrix to look like:
0 0 1
1 1 1
0 0 2
Thank you for your help, it is very appreciated !

Respuestas (2)

Azzi Abdelmalek
Azzi Abdelmalek el 19 de Nov. de 2012
A=[0 0 1;0 0 2;1 1 1];
[~,idx]=sort(sum(A.^2,2))
out=A(idx,:)
  1 comentario
Jan
Jan el 19 de Nov. de 2012
This is faster than the arrayfun approach, but of course this matters for larger matrices only.

Iniciar sesión para comentar.


Yowh
Yowh el 19 de Nov. de 2012
Here .. I think this will work ..
A = [0 0 1;0 0 2;1 1 1;0 0 0];
ans = sortrows(A, [3 2 1])

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