How to plot this code correctly?

32 visualizaciones (últimos 30 días)
Jay
Jay el 21 de Nov. de 2012
tt=1000;
B=1700;
b=0.0013;
sigma=0.0099;
t = 0 : 1 : tt;
for K = 1 : length(t)
p(K) = (B-(b*t(K)))/(sigma);
end
p(K)= roundn(p,-1);
p(K)=p;
if p==0.0
l=.5*k;
elseif p==0.1
l=.5478*k;
elseif p==0.2
l=.5793*k;
elseif p==0.3
l=.6255*k;
elseif p==0.4
l=.6554*k;
elseif p==0.5
l=.6985*k;
elseif p==0.6
l=.7257*k;
elseif p==0.7
l=.7642*k;
elseif p==0.8
l=.7881*k;
elseif p==0.9
l=.8212*k;
elseif p==1.0
l=.8413*k;
elseif p==1.1
l=.8686*k;
elseif p==1.2
l=.8849*k;
elseif p==1.3
l=.9066*k;
elseif p==1.4
l=.9192*k;
elseif p==1.5
l=.9357*k;
elseif p==1.6
l=.9452*k;
elseif p==1.7
l=.9573*k;
elseif p==1.8
l=.9641*k;
elseif p==1.9
l=.9726*k;
elseif p==2.0
l=.9772*k;
elseif p==2.1
l=.9830*k;
elseif p==2.2
l=.9861*k;
elseif p==2.3
l=.9898*k;
elseif p==2.4
l=.9918*k;
elseif p==2.5
l=.9941*k;
elseif p==2.6
l=.9953*k;
elseif p==2.7
l=.9967*k;
elseif p==2.8
l=.9974*k;
elseif p==2.9
l=.9982*k;
elseif p==3.0
l=.9987*k;
elseif p>3.0
l=1*k;
elseif p==-0.1
l=.4522*k;
elseif p==-0.2
l=.4207*k;
elseif p==-0.3
l=.3745*k;
elseif p==-0.4
l=.3446*k;
elseif p==-0.5
l=.3015*k;
elseif p==-0.6
l=.2743*k;
elseif p==-0.7
l=.2358*k;
elseif p==-0.8
l=.2119*k;
elseif p==-0.9
l=.1788*k;
elseif p==-1.0
l=.1587*k;
elseif p==-1.1
l=.1314*k;
elseif p==-1.2
l=.1151*k;
elseif p==-1.3
l=.0934*k;
elseif p==-1.4
l=.0808*k;
elseif p==-1.5
l=.0643*k;
elseif p==-1.6
l=.0548*k;
elseif p==-1.7
l=.0427*k;
elseif p==-1.8
l=.0359*k;
elseif p==-1.9
l=.0274*k;
elseif p==-2.0
l=.0228*k;
elseif p==-2.1
l=.0170*k;
elseif p==-2.2
l=.0139*k;
elseif p==-2.3
l=.0102*k;
elseif p==-2.4
l=.0082*k;
elseif p==-2.5
l=.0059*k;
elseif p==-2.6
l=.0047*k;
elseif p==-2.7
l=.0033*k;
elseif p==-2.8
l=.0026*k;
elseif p==-2.9
l=.0018*k;
elseif p==-3.0
l=.0013*k;
else
l=0*k;
end
plot(t, p)
  1 comentario
Matt Fig
Matt Fig el 21 de Nov. de 2012
Editada: Matt Fig el 21 de Nov. de 2012
That code errors, so there is nothing to plot!
Also, you are not going to get the results you expect from that massive IF block. You are comparing floating points for equality, which is a bad idea. I also wonder if you are hoping the IF block will pick out each element of p one at a time... it won't.

Iniciar sesión para comentar.

Respuesta aceptada

Walter Roberson
Walter Roberson el 21 de Nov. de 2012
Read the documentation on histc() and in particular pay attention to the multiple-output version of it.

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