why this code not displaying else part

the following code is only displaying the if part even if the value is less than 0.6

y = sprintf('%.1f',rand(1))
if y>0.6
    disp('the value is false')
else 
    disp('true') 
 end 

Answer 1

[madhan ravi]

Remove sprintf()

[madhan ravi]

And in fact your if else can be replace with

Condition = y > .6 % 1 means true and 0 means false

[abdul rehman]

This is only working for one condition

[madhan ravi]

Huh? More illustrations needed with an example. Because the comment is totally vague.

[abdul rehman]

actually I want a random number btween 0 and1 the code give me answer like 0.3555 which is 4 decimal place, so i want to round it of to 0.3 and that use same random number in condition

[madhan ravi]

doc round

[abdul rehman]

a=rand(1)

round(0.333)

the answer is 0 I wnat 0.3

[madhan ravi]

Read the input arguments of that function in documentation ;).

>> round(.3555,1)

ans =

    0.4000

>> 

[abdul rehman]

no sir any of your suggestion is not working

[madhan ravi]

A totally vague comment not useful to understand at all.

[madhan ravi]

”madhan ravi your answars are incomplete“

Yes because it’s your homework and not mine. Don’t expect others to do your homework. Make sure to READ the documentations properly before bashing others!

”you must know round only take single argument. Sorry but you are wasting time and your as well“

Not sure who’s wasting whose time here.Did you even read the documentation ?

https://www.mathworks.com/help/matlab/ref/round.html#buftmpz-type

[Steven Lord]

As of release R2014b the round function has a syntax that accepts multiple inputs. abdul rehman, are you using a release prior to release R2014b? If so that would explain why madhan ravi's suggestion didn't work for you.

[madhan ravi]

Thanks Steven.

[abdul rehman]

thanks Steven this was the actural issue. and sorry madhan