Take string input and reformat as cell array
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I would like to convert a string into a cell array. Here is a small example of string:
[{"ts": "2018-07-03T06:30:07", "v": 1.0}, {"ts": "2018-07-03T06:30:12", "v": 0.0}, {"ts": "2018-07-03T08:41:06", "v": 1.0}]
I would like to convert this into the following format:
[ datetime ] [number]
The ts and v refer to timestamp and value, and are not important to keep.
I believe using the textscan is an efficient way to do it, however I cannot figure out how to use it properly, any help is appreciated!
2 comentarios
Stephen23
el 10 de Jun. de 2020
@Connor Brackley: please upload a sample of your data by clicking the paperclip button.
Connor Brackley
el 10 de Jun. de 2020
Respuesta aceptada
Más respuestas (1)
Ameer Hamza
el 10 de Jun. de 2020
Editada: Ameer Hamza
el 10 de Jun. de 2020
Try this
str = fileread('test.txt');
dts = regexp(str, '"ts": "([0-9:T-]*)"', 'tokens');
vs = regexp(str, '"v": ([0-9.]*)', 'tokens');
dts = cellfun(@(x) datetime(x, 'InputFormat', 'yyyy-MM-dd''T''HH:mm:ss'), [dts{:}]);
vs = cellfun(@str2double, [vs{:}]);
T = table(dts.', vs.', 'VariableNames', {'DateTime', 'V'});
disp(T)
Result
DateTime V
____________________ _
03-Jul-2018 06:30:07 1
03-Jul-2018 06:30:12 0
03-Jul-2018 08:41:06 1
1 comentario
Connor Brackley
el 10 de Jun. de 2020
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