Help with infinite while loop

I need to create a simple script that take a number, checks if it odd or even. If it's even: divide by two, if it's odd: multiply by 3 add 1. The script is supposed to repeat this check and calculation until the output reaches a value of one. I've tried the following while loop which calculates the first value but then infinity spits out this same value. Thanks in advance!
clear
disp('Please input student number')
ID = input('SI#: ');
if mod(ID,2) == 0
out = ID/2
else out = ID.*3+1
end
while out > 1
if mod(ID,2) == 0
out = ID/2
else out = ID.*3+1
end
end

6 comentarios

Matt J
Matt J el 24 de Nov. de 2012
It doesn't seem easy to prove that this will eventually converge to 1. Is it a well-known result from somewhere?
Matt Fig
Matt Fig el 24 de Nov. de 2012
@Matt J - AFAIK, it is not proven. But it has been extensively tested and never found to fail. Look up Collatz conjecture.
Azzi Abdelmalek
Azzi Abdelmalek el 24 de Nov. de 2012
Tested in a loop for k=1:10^6 with randi, never fail.
Walter Roberson
Walter Roberson el 24 de Nov. de 2012
For example, my BOINC client just finished testing 8E12 numbers starting from 2377489401671993502056 without finding any counter-example.
Matt J
Matt J el 24 de Nov. de 2012
OK. Glad I didn't spend my day trying to prove it :)
Jan
Jan el 25 de Nov. de 2012
Editada: Jan el 25 de Nov. de 2012
It is not proved. See http://en.wikipedia.org/wiki/Collatz_conjecture. You can earn 500$ and the Fields medal when you prove it, but this would conflict with the term " algorithmically undecidable".

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Respuestas (3)

Matt Fig
Matt Fig el 24 de Nov. de 2012
Editada: Matt Fig el 24 de Nov. de 2012

0 votos

The problem is that ID never changes in your loop so you are just doing the same thing over and over. Change all 'out' variables to 'ID' and your code should work fine.
Jan
Jan el 25 de Nov. de 2012
Editada: Jan el 25 de Nov. de 2012

0 votos

It is a good idea to ask Google, in this case for "3N+1 Wiki". You find explanations, theorems, algorithms and visualizations, ... Enough material to solve the homework.

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el 24 de Nov. de 2012

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