how to open a file from the previous folder

Hello, I have a folder hierarchy like the one in the image, I'm running a script from folder B and what I want is to open an image that is in folder C, but the path to it can change, that is, I want the code to be the same regardless of whether the folder A is on the desktop or in my documents for example.

Does anyone know how to program that?

Answer 1

[Geoff Hayes]

Alajendro - you should be able to use pwd to determine the current folder, and then "navigate" up one directory to A and then down one to C. I'm assuming that you know the name of folder C.

currentPath = pwd;
folderCName = 'someFolderName';
pathToFolderC = [pwd filesep '..' filesep folderCName filesep];

I had thought about using fullfile to build the pathToFolderC but (on my version of MATLAB),the '..' was not being included in the path.

[Alejandro Fernández]

But i'm located on B, so i have to go back to A and then up to C, this code works if y was firstly located on A... no¿

[Geoff Hayes]

Based on your picture, I assumed that both B and C were folders within A. Is my assumption false? Or are B and C not sub-folders within A?

[Alejandro Fernández]

That’s true, B and C are sub-folders within A

[Geoff Hayes]

So the pwd will give you the current path which should be B. Say something like "/users/geoffh/folderB". We append the .. to get "/users/geoffh/folderB/.." which means that we now have the path to folder A. We then append the folder C name to get "/users/geoffh/folderB/../folderC" which means that we now have the path to folder C.

[Alejandro Fernández]

Wow sorry, the code you give me bellow works, thank you so much!!!!

[Geoff Hayes]

No problem! :)

[Stephen23]

" had thought about using fullfile to build the pathToFolderC but (on my version of MATLAB),the '..' was not being included in the path."

Odd. It works here:

folderCName = 'someFolderName';
pathToFolderC = fullfile(pwd,'..',folderCName)

pathToFolderC = '/users/mss.system.g8rKA4/../someFolderName'

Answer 2

[Amine BEROUAKEN]

Hello, you can use this code

imagePath = fileparts(pwd) + "\FloderCName\imageName.png";

Answer 3

[Stephen23]

Note that there is absolutely no need to call PWD. Simply use '.' to refer to the current directory:

relativePathToC = './../C';