Creating a vector field

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Johannes
Johannes el 27 de Nov. de 2012
Comentada: Nitin Phadkule el 9 de Oct. de 2021
Hello everybody,
I am trying to create a vector field. The vector at each point is combined out of two others.
I tried
[x,y] = meshgrid(-2:.2:2,-2:.2:2) ; to create the points I want to take a look at
VectorX = [x./(2*pi*(x.^2+y.^2)),0]; is the Vector in the "x" direction
VectorY = [0,y./(2*pi*(x.^2+y.^2))]; is the Vector in the "y" direction
Vectortoplot = [(x./(2*pi*(x.^2+y.^2))),(y./(2*pi*(x.^2+y.^2)))];
quiver(x,y,Vectortoplot)
But all I get is an empty coordinat system form 0 to 1 in 0.1 steps in each direction. I am a little confused.
If you could help me, I would be very thankful.
  2 comentarios
Jan
Jan el 28 de Nov. de 2012
Please learn how to format code in the forum. Inserting white lines does not look fancy.
Johannes
Johannes el 29 de Nov. de 2012
I know, i am new in matlab, and this was the fastest way for me.
I will try to do that in the future, however i would be thankful for some help

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Respuestas (1)

Babak
Babak el 28 de Nov. de 2012
Editada: Babak el 28 de Nov. de 2012
I don't know why you put a zero at the end of VectorX and a zero at the beginning of VectorY which makes those lines incorrect.
Your usage of quiver doesn't seem to be proper either. quiver needs 4 inputs. See
doc quiver
on that.
Here's what I ran:
[x,y] = meshgrid(-2:.2:2,-2:.2:2) ; %to create the points I want to take a look at
VectorX = [x./(2*pi*(x.^2+y.^2))]; %is the Vector in the "x" direction
VectorY = [y./(2*pi*(x.^2+y.^2))]; %is the Vector in the "y" direction
Vectortoplot = [(x./(2*pi*(x.^2+y.^2))),(y./(2*pi*(x.^2+y.^2)))];
% size(x)
% size(y)
% size(VectorX)
% size(VectorY)
quiver(x,y,VectorX,VectorY)
  3 comentarios
Rupchand Sutradhar
Rupchand Sutradhar el 5 de Jul. de 2021
Editada: Rupchand Sutradhar el 5 de Jul. de 2021
how can I set the length of arrow ?
Nitin Phadkule
Nitin Phadkule el 9 de Oct. de 2021
quiver(x,y,VectorX,VectorY,0)
add 0

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