Why do I get error incorrect use of '=' operator?
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현우 이
el 19 de Jun. de 2020
Comentada: 현우 이
el 19 de Jun. de 2020
I made the drunk man simulation. But if I run this, I get the error message Error: Incorrect use of '=' operator. To assign a value to a variable, use '='. To compare values for equality, use '=='.
and if I change = to <=, I get the error message
while (s<10 && s >-10 && i<100)
↑
Error: Illegal use of reserved keyword "while".
Why does this happen and how can I fix it? Thanks a lot in advance.
This is my code.
alive = 0
success = 0
dead = 0
p = 0.5
for n=1:1000
{
i = 0
s = 0
while (s<10 && s >-10 && i<100)
x = rbinom(1, 1, p);
if(x == 1)
s = s-1;
else
s = s+1;
i = i+1;
end
if(s == 10)
success = success + 1;
end
if(s == -10)
dead = dead + 1;
end
end
if(s<10 &&s > -10)
alive = alive +1;
end
barplot(c(success, dead, alive))
0 comentarios
Respuesta aceptada
Nipun Agarwal
el 19 de Jun. de 2020
Hey,
The problem comes in because of curly braces after the for loop. MATLAB syntax never allows curly braces after the for loop. I have updated the code of yours and indented it properly for you to have a better standing.
alive = 0;
success = 0;
dead = 0;
p = 0.5;
for n=1:1000
i = 0;
s = 0;
while (s<10 && s >-10 && i<100)
x = 1;
if(x == 1)
s = s-1;
else
s = s+1;
i = i+1;
end
end
if(s == 10)
success = success + 1;
end
if(s == -10)
dead = dead + 1;
end
if(s<10 &&s > -10)
alive = alive +1;
end
end
barplot(c(success, dead, alive))
2 comentarios
Stephen23
el 19 de Jun. de 2020
The MATLAB Editor's default indentation rules give this even clearer version:
alive = 0;
success = 0;
dead = 0;
p = 0.5;
for n=1:1000
i = 0;
s = 0;
while (s<10 && s >-10 && i<100)
x = 1;
if(x == 1)
s = s-1;
else
s = s+1;
i = i+1;
end
end
if(s == 10)
success = success + 1;
end
if(s == -10)
dead = dead + 1;
end
if(s<10 &&s > -10)
alive = alive +1;
end
end
barplot(c(success, dead, alive))
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