no use of for loop

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Rica
Rica el 29 de Nov. de 2012
Hi!
n=[0:0.01:0.5];
f=[2:0.01:3];
for k=1:length(n)
for l=1:length(f)
beta=n(k).*Dc/Dw
omega=2e9*pi*f(l);
epsilon=3./(1+j*omega*tau);
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)(epsilon_cc));
end
end
is there any advice to programm this without using for loops?
Thank you
EDIT CORRECTED PROGRAM:
Hi sorry. here is the corrected program.
n=[0:0.01:0.5];
f=[2:0.01:3];
epsilon_cc=2
for k=1:length(n)
for l=1:length(f)
beta=n(k);
omega=2e9*pi*f(l);
epsilon=3./(1+j*omega*tau);
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)*(epsilon_cc))
end
end
thank you for your help!
  2 comentarios
Azzi Abdelmalek
Azzi Abdelmalek el 29 de Nov. de 2012
What are sizes of Dc , omega
Wayne King
Wayne King el 29 de Nov. de 2012
You should make your post so that people can actually execute your code. You do not give Dc, or Dw, and what is this line
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)(epsilon_cc));
are you multiplying 1-beta and epsilon_cc?

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Respuesta aceptada

Jan
Jan el 29 de Nov. de 2012
Editada: Jan el 29 de Nov. de 2012
The variable "epsilon" does not change its value inside the loop, so move its calculation out of the loop.
"beta" does not change its value inside the inner loop, so move to the outer loop.
The variables "j", "epsilon_cc", "Dc" and "Dw" are not defined in the code snippet. We cannot guess their values or if they are functions.
The expression "(1-beta)(epsilon_cc)" is not valid in Matlab. Perhapos you forgot a "*".
Please cleanup the code at first.

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