Transpose a structure with named fields ?
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Flynn McGuire
el 24 de Jun. de 2020
Comentada: Flynn McGuire
el 24 de Jun. de 2020
I have a struct that looks like this:
i.g. labeled fields
I have been trying to apply this example:
% Fake data
s(1).f = rand(1,100);
s(2).f = rand(1,100);
s(3).f = rand(1,100);
c = arrayfun(@(x)x.f.', s, 'UniformOutput', 0);
s = cell2struct(c, 'f');
but I think it doesn't work becuase I have labeled feilds.
Any ideas?
1 comentario
Stephen23
el 24 de Jun. de 2020
Editada: Stephen23
el 24 de Jun. de 2020
"Any ideas?"
Your screenshot shows a scalar structure with multiple fields.
Your example code has a non-scalar structure with one field.
It is not clear how that example would apply to the scalar structure shown in your screenshot.
You could use structfun like Mehmed Saad showed, or simply loop over the fieldnames:
Respuesta aceptada
Mehmed Saad
el 24 de Jun. de 2020
if all of them are scalar then this will work
s_mod=structfun(@transpose,s,'UniformOutput',false)
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