file name extraction from load file

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Akhtar Rind el 3 de Jul. de 2020

Comentada: Akhtar Rind el 4 de Jul. de 2020

I have load data file to extract data and plots.

A typical file name would be '01_02_20_Cu_1.csv' and I use this as

A1= readcell('01_02_20_Cu_1.csv');

How can I get file name "01_02_20_Cu_1" from load data file as text format?

Kawin Kumaran el 3 de Jul. de 2020

fileparts() function can be used to extract file name .

file = '01_02_20_Cu_1.csv';
[~,name,~] = fileparts(file)

The result will be :

name : '01_02_20_Cu_1'

Please refer the following documentation for more information .

Akhtar Rind el 4 de Jul. de 2020

Fantastic. It worked. Many thanks Kawin.

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