replace [ ] in an array with 0's
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alpedhuez
el 7 de Jul. de 2020
talks about replace [] with 0's for one column. But suppose I have a table with many columns and I want to run this operation for multiple colmns. Is there any way simpler than writing another loop?
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Image Analyst
el 7 de Jul. de 2020
tables use functions like ismissing() and fillmissing():
newTable = fillmissing(badTable, 'constant', 0)
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KSSV
el 7 de Jul. de 2020
You can get all the emtpy functions in a cell using cellfun ..
idx = cellfun(@isempty,C) ; % get empty cells in a cell array C
C(idx) = 0 ; % replace with zero
Note that, cellfun also uses loop inside.
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KSSV
el 7 de Jul. de 2020
You run on each column of a table..
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dpb
el 7 de Jul. de 2020
Did you try it? I dunno, don't have your table but can only have empty [] in cell array so the table column content must be a cell it would seem...
Again, w/o a sample piece of data to work on it's tough...
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