How to read Audio File into Vector?

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dieter alfred
dieter alfred el 15 de Jul. de 2020
Comentada: Walter Roberson el 29 de Dic. de 2025 a las 20:52
Hello, I have to read a Audio File (.wav) into a vector.
I know how to plot it:
info = audioinfo('sound.wav');
[y, Fs] = audioread('sound.wav');
t = 0:1/Fs:info.Duration;
t = t(1:end-1);
plot(t,y);
xlabel('Time');
ylabel('Audio Signal');
But this Sript does not read the Audio into a Vector.
I also tried to read every single Sample, but this is to complex and I get error after error. Is there a simple way to do this?
  2 comentarios
Cris LaPierre
Cris LaPierre el 15 de Jul. de 2020
It would be helpful if you could share the error messages as well as your sound.wav file.
dieter alfred
dieter alfred el 15 de Jul. de 2020
Sorry, I cannot upload the file, because the forum doesnt accept the .wav filetype. And I have already deleted the code with the error messages. But next time I will upload everything.

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Respuesta aceptada

Sugar Daddy
Sugar Daddy el 15 de Jul. de 2020
Editada: Sugar Daddy el 15 de Jul. de 2020
[y, Fs] = audioread('sound.wav');
sound_duration = length(y)/Fs;
t = 0:1/Fs:sound_duration;
t = t(1:end-1);
%%
soundsc(y,Fs);
%%
plot(t,y);
xlabel('Time');
ylabel('Audio Signal');
  3 comentarios
bob bob
bob bob el 21 de Dic. de 2024
Any idea on how to reduce the # of points? I am trying to get the SVG to use in a graphic design setting so I will be altering the shape more in Illustrator but I would like to reduce the point by quite a bit
Walter Roberson
Walter Roberson el 29 de Dic. de 2025 a las 20:52
I suggest using resample
If you do not have the Signal Processing Toolbox, then you could instead try using imresize

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Más respuestas (1)

Walter Roberson
Walter Roberson el 29 de Dic. de 2025 a las 20:49
An audio file would not be read into a vector in the case where the audio file had multiple channels.
%approach #1
[y, Fs] = audioread('sound.wav');
y = y(:,1); %take the left channel only
t = (0:length(y)-1)/Fs;
%approach #2
[y, Fs] = audioread('sound.wav');
y = mean(y,2); %average all channels
t = (0:length(y)-1)/Fs;
Note that the code
t = 0:1/Fs:info.Duration;
t = t(1:end-1);
could result in a time vector that was one element too long or too short because of round-off errors in accumulating the 1/Fs in the colon operation.

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