Borrar filtros
Borrar filtros

Display row from Excel file in Matlab

1 visualización (últimos 30 días)
Javier
Javier el 18 de Jul. de 2020
Comentada: Javier el 19 de Jul. de 2020
Hello there, I am trying to generate a random number (n) to then look for the data in the row n in a Excel file.
When I used
X = readtable('file.xlsx')
instead of
X = importdata('file.xlsx')
the program worked fine, but I want to know how to make it work with the function importdata as well.
It gives me this error Index in position 1 exceeds array bounds (must not exceed 1).
This is the code I used:
X = importdata('file.xlsx')
n = input('Number of participants: ');
r = randi(n)
disp('The winner is: '+string(r))
disp('The winner data is: ')
disp(X(r,:))
  2 comentarios
Cris LaPierre
Cris LaPierre el 18 de Jul. de 2020
Without knowing more about your file, we can't offer much help. The error message would suggest X only contains a single row. Check that X exists in your Workspace, and is the expected size.
Javier
Javier el 19 de Jul. de 2020
It has 2 columns and 5 rows. In the first column are the numbers 1 to 5 and in the second column are names.

Iniciar sesión para comentar.

Respuesta aceptada

Cris LaPierre
Cris LaPierre el 19 de Jul. de 2020
Editada: Cris LaPierre el 19 de Jul. de 2020
The error message you are seeing is because importdata returns the results in a stucture. Numeric data would be in X.data, text data in X.textdata. Also from the documentation:
  • For ASCII files and spreadsheets, importdata expects to find numeric data in a rectangular form (that is, like a matrix).
Tables allow you to mix data types in the same row. Here, you will need to build the disp command by combining the two separate structure fields. Perhaps something like this:
disp([X.data(r) X.textdata(r)])
  1 comentario
Javier
Javier el 19 de Jul. de 2020
It worked perfectly. Thank you so much.

Iniciar sesión para comentar.

Más respuestas (0)

Productos


Versión

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by