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What is the problem in these code?
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Hello friends, I have a code like this:
for x=1:50
Nrows=size(orj_matr,1)
new_matr=randperm(Nrows)
new_matr=new_matr(1:50)
a(:,:,x)=orj_matr(new_matr,:)
end
When I wrote this codes to MATLAB, I have 50 different (50 rows-10 columns) matrices. Like this:
a(:,:,1) , a(:,:,2), a(:,:3), …………a(:,:,50)
And I want to calculate f1 and f2 for these 50 different matrices. When I wrote like this there was an error saying “Indexing must appear last in an index expression”.
f1=sum(a(:,:,x) (:,1:2:end),2);
f2=sum(a(:,:,x) (:,2:2:end),2);
What is the mistake in these codes? Please help me...
1 comentario
Jan
el 19 de Dic. de 2012
Editada: Jan
el 19 de Dic. de 2012
It would be useful if you explain, what the the expression "a(:,:,x) (:,1:2:end)" should do. As long as it is no valid Matlab syntax, a suggestion for improvement requires guessing what you want to achieve. And an answer based on guesses can be worse than no answer.
Respuestas (2)
Jürgen
el 19 de Dic. de 2012
Editada: Jürgen
el 19 de Dic. de 2012
Hi,
sum(a(:,:,x) (:,1:2:end),2); is not correct , I think What do you want to do there? '(:,1:2:end)' is referring to the index and it put at the right place regards,J
3 comentarios
José-Luis
el 19 de Dic. de 2012
I would recommend you read up on indexing.
a(:,:,x) (:,1:2:end)
is not a valid expression. I am guessing that what you want is something along the lines
squeeze(sum(a(:,1:2:end,:),2))
Also, please edit your code to make it more readable. That might attract more answers.
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