Stopping my function from doing iteration (infinite while loop)

After achieving the desired result the loop continues, how can i stop this? if truefunction y = mysqrt(x,y0,tol) % this function calculates the square root of a number x as y given the % less appropriate guess y0. The function ceases to iterate when the the % difference between y0 and y is less than 1e-3.
y = (y0 + (x/y0))/2;
y = (y + (x/y))/2;
while abs(y-y0)>tol
y = (y + (x/y))/2
end

1 comentario

woops forgot to add the top line of the script:
function y = mysqrt(x,y0,tol)function

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 Respuesta aceptada

Azzi Abdelmalek
Azzi Abdelmalek el 21 de Dic. de 2012
Editada: Azzi Abdelmalek el 21 de Dic. de 2012
function y = mysqrt(x,y0,tol)
y = (y0 + (x/y0))/2;
y = (y + (x/y))/2;
while abs(y^2-x)>tol
y = (y + (x/y))/2
end

5 comentarios

ooooooooooooooooohhhhhhhhhhhhh that makes sense!!!! thanks!!!
how about when 2 iterations are closer than tol?
The while loop will be skipped. The result will be fine
No, i mean by setting that as the condition. Is it possible?
It's not clear

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Más respuestas (1)

John Petersen
John Petersen el 21 de Dic. de 2012
Editada: John Petersen el 21 de Dic. de 2012
function y = mysqrt(x,y0,tol)
y = (y0 + (x/y0))/2;
while abs(y-y0)>tol
y0 = y;
y = (y + (x/y))/2;
end
Now I see Azzi's answer which is better because it tests against the desired result.

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Más información sobre Loops and Conditional Statements en Centro de ayuda y File Exchange.

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A K
el 21 de Dic. de 2012

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