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[EDIT: 20110512 17:03 EDT - reformat - WDR]
I keep getting the error Undefined function or method 'Newton' for input arguments of type 'inline'. I'm doing newtons method and I can't figure out what that error means and what part of my code is wrong.
function x = Newton(f, fp, x, nmax, error)
x=1;
e=2.71828;
f(x)=inline('(x)*(5000)*(e^(-x)))-((100)+(0.73)*(5000)*(e^(-x))');
fp(x)=inline('-5000*(e^(-x))*(x-1.73)');
nmax = 10;
error = 1.0e-15;
x = Newton(f,fp,x,nmax,error)
fprintf('x(0) = %10g \n', x)
for n = 1:nmax
      d = f(x)/fp(x);
      x = x - d;
      fprintf('x(%i) = %10g \n', n, x)
      if abs(d) < error
          fprintf('Converged! \n')
          return
      end
  end
  end
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Respuesta aceptada
  Paulo Silva
      
 el 18 de Abr. de 2011
        There's no Newton function on MATLAB current path or any other path that MATLAB is aware, you get the same error for
whateverfunctionisayso(inline('x'))
This should be your script:
x=1; 
f=inline('x*5000*exp(-x)-(100+0.73*5000*exp(-x))'); 
fp=inline('-5000*exp(-x)*(x-1.73)'); 
nmax = 10; 
error = 1.0e-15; 
x = Newton(f,fp,x,nmax,error) 
fprintf('x(0) = %10g \n', x)
And this is your function:
function x = Newton(f, fp, x, nmax, error)
for n = 1:nmax 
 d = f(x)/fp(x); 
 x = x - d; 
 fprintf('x(%i) = %10g \n', n, x) 
 if abs(d) < error 
 fprintf('Converged! \n') 
 return 
 end 
end 
end
Save the function to the current path or another that MATLAB is aware of and run the script.
16 comentarios
Más respuestas (1)
  Matt Tearle
    
 el 18 de Abr. de 2011
        That message generally means that your function file isn't on the MATLAB path. Is Newton.m in your current directory?
There are some other issues with your code, but they wouldn't cause that error.
5 comentarios
  Paulo Silva
      
 el 19 de Abr. de 2011
				Matt is also right about using function handles instead of inline expressions but I wouldn't bother much with it, all should work good with your current code.
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