How to avoid patch color being included in legend ?
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Mahesh Babu Dhanekula
el 7 de Ag. de 2020
Comentada: Image Analyst
el 7 de Ag. de 2020
I would like to know how to remove the patcharea being represented in legend. I have attached the code and outputs when patch command is included and not used. When patch is used to highlight a portion of plot its color is getting indicated rather than the linestyle and line color in legend. Also the thickening of xaxis and yaxis in upper and right side borders disappears when more than one patch command has used. This can be seen from the figure named patch. Please let me know how to fix this issue. Due to the limitation on number of pictures can be attached i have added the picture when patch command is used.
Edit: Through the usage of handles legend issue got solved. But the boder issue persists. Have a look at the picture named patch1 in comments.
clc;
clear all;
close all;
x = linspace(-10,10,200);
y = sin(4*x);
y1 = sin(x);
figure;
patch([2 5 5 2], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
hold on
patch([-5 -2 -2 -5], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
hold on
plot(x,y,'r');
hold on
plot(x,y1,'g');
hold off
grid on;
legend({'sin(4*x)','sin(x)'});
Respuesta aceptada
Image Analyst
el 7 de Ag. de 2020
Editada: Image Analyst
el 7 de Ag. de 2020
Try this:
clc;
clear all;
close all;
x = linspace(-10,10,200);
y = sin(4*x);
y1 = sin(x);
figure;
hold on
patch([2 5 5 2], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
patch([-5 -2 -2 -5], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
h1 = plot(x,y,'r');
h2 = plot(x,y1,'g');
hold off
grid on;
legend([h1 h2],'sin(4*x)','sin(x)');
box on
Alternatively you can set the "Annotation.LegendInformation.IconDisplayStyle" property of the patch object to 'off':
period = 3;
x = linspace(-10,10,200);
y = sin(2 * pi * x / period);
y1 = sin(x);
figure;
hold on
p1 = patch([2 5 5 2], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
p2 = patch([-5 -2 -2 -5], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
% Tell legend not to include the patches.
p1.Annotation.LegendInformation.IconDisplayStyle = 'off';
p2.Annotation.LegendInformation.IconDisplayStyle = 'off';
h1 = plot(x,y,'r', 'LineWidth', 2);
h2 = plot(x,y1,'g', 'LineWidth', 2);
hold off
grid on;
legend('sin(4*x)','sin(x)');
% Turn on border:
box on
4 comentarios
Image Analyst
el 7 de Ag. de 2020
Not that I know of, other than the obvious.
You can search for Waterloo - a third party package:
I guess it's an alternative to export_fig.
The Mathworks developers told us that exportgraphics() can do most, but not all (yet) that export_fig can do. Their goal is to bring that functionality in-house to relieve Yair Altman from the burden of maintaining export_fig.
Más respuestas (2)
KSSV
el 7 de Ag. de 2020
Editada: KSSV
el 7 de Ag. de 2020
clc;
clear all;
close all;
x = linspace(-10,10,200);
y = sin(4*x);
y1 = sin(x);
figure;
hold on
patch([2 5 5 2], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
patch([-5 -2 -2 -5], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
h1 = plot(x,y,'r');
h2 = plot(x,y1,'g');
hold off
grid on;
legend([h1 h2],'sin(4*x)','sin(x)');
3 comentarios
Arthur Roué
el 7 de Ag. de 2020
You need to explicit legend and object handle for each line / patch when calling legend function
hY = plot(x,y,'r');
hold on
hY1 = plot(x,y1,'g');
hold off
grid on;
legend([hY, hY1], {'sin(4*x)','sin(x)'});
4 comentarios
Arthur Roué
el 7 de Ag. de 2020
Switch 'Box' property of your axes to 'on' in order to display all borders
x = linspace(-10,10,200);
y = sin(4*x);
y1 = sin(x);
figure;
hAxe = axes(gcf, 'NextPlot', 'add', 'Box', 'on');
patch([2 5 5 2], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
patch([-5 -2 -2 -5], [[1 1]*(-1) [1 1]*(1)], 'y', 'FaceAlpha',0.3, 'EdgeColor','none');
hY = plot(x,y,'r');
hY1 = plot(x,y1,'g');
grid on;
legend([hY, hY1], {'sin(4*x)','sin(x)'});
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