defining divideblock function for feedforward net
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i've used 'divideblock' function as follow:
net.divideFcn = 'divideblock'; net.divideParam.trainRatio = 0.6; net.divideParam.valRatio = 0.20; net.divideParam.testRatio = 0.20;
for feedforward neural network. when i run the program, the details of the network will be displayed. the problem is, it display 2 neural network details. the first set will show
net =
Neural Network
. . . .
functions:
adaptFcn: 'adaptwb'
adaptParam: (none)
derivFcn: 'defaultderiv'
divideFcn: 'dividerand'
and the other one shows
functions:
adaptFcn: 'adaptwb'
adaptParam: (none)
derivFcn: 'defaultderiv'
divideFcn: 'divideblock'
divideParam: .trainRatio, .valRatio, .testRatio
. . . .
is it suppose to be like this when we define 'divideblock' as a divide function? i expect it to display only 1 and not both, since i dont need my data to be randomized.
thank you. :)
1 comentario
Greg Heath
el 7 de En. de 2013
Editada: Greg Heath
el 7 de En. de 2013
Post your code.
P.S. Use fitnet for regression and patternnet for classification. Both call feedforwardnet and provide better output info. There is no reason to use feedforwardnet.
Respuesta aceptada
Greg Heath
el 14 de Jun. de 2013
The default 'dividerand' exists at net creation: net = fitnet(H)
Specifying 'divideblock' then replaces it.
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