Evaluating 2D function on 2D grid without using "for" loops

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Luqman Saleem
Luqman Saleem el 21 de Ag. de 2020
Comentada: Sara Boznik el 22 de Ag. de 2020
I have a function f(x,y) and I want to evaluate it on x,y grid. For example,
f = @(x,y) x^2+y^2;
x = 1:10;
y = 1:5;
%one way to do it is using for loops.
for x=1:10
for y=1:5
result(x,y) = f(x,y);
end
end
Is there any way do it without using "for" loops?
  1 comentario
Stephen23
Stephen23 el 22 de Ag. de 2020
"Is there any way do it without using "for" loops?"
Why do you want to avoid for loops? Contrary to what some beignners think, (well-written) for loops are not slow.
Is result preallocated before the loops?

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Respuestas (1)

Sara Boznik
Sara Boznik el 21 de Ag. de 2020
f = @(x,y) x.^2+y.^2;
x = 1:10;
y = 1:5;
[X,Y] = meshgrid(x,y);
meshc(X, Y, f(X,Y))
grid on
You can try that.
Best of luck.
  2 comentarios
Luqman Saleem
Luqman Saleem el 21 de Ag. de 2020
Actually, the original function is very large and I will have to put (.) in front of all "^" or "*" operators. It also involves matrix multiplication, so, it will just be very messy if I try to put ".". Is there any way to avoid doing it?
Sara Boznik
Sara Boznik el 22 de Ag. de 2020
Sorry, I do not know faster way

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