Respuesta aceptada

Star Strider
Star Strider el 7 de Sept. de 2020
Try this:
figure
hp{1} = polarplot([45 160; 0 0]*pi/180, [1 1; 0 0], '--k', 'DisplayName','Induction');
hold on
hp{2} = polarplot([160; 0]*pi/180, [1; 0], '-k', 'DisplayName','Field');
polarplot([40 50; 45 45]*pi/180, [0.8 0.8; 1 1], '-k')
polarplot([155 165; 160 160]*pi/180, [0.8 0.8; 1 1], '-k')
hold off
lgd = legend([hp{1}(1), hp{2}(1)], 'Induction','Field', 'Location','southoutside');
title(lgd, '\itB\rm at 45°')
producing:
.

2 comentarios

Hassan Abdelazeem
Hassan Abdelazeem el 7 de Sept. de 2020
Thank you indeed for your help really thank you
Star Strider
Star Strider el 7 de Sept. de 2020
As always, my pleasure!

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Más respuestas (1)

Hassan Abdelazeem
Hassan Abdelazeem el 7 de Sept. de 2020

0 votos

The figure appear but I recieved this error message as in the attachment file
Regards

3 comentarios

Star Strider
Star Strider el 7 de Sept. de 2020
There are too many spaces in the handle vector of the legend call. Cell arrays are comma-separated lists, and if spaces appear between the subscript references, this confuses MATLAB.
Note that the extra spaces in the title call will likely also throw an error. This will cause problems for the text interpreter, since spaces in a character vector are significant, and it will not interpret the TeX calls ‘\it’ and ‘\rm’ correctly.
Please just use my code as I wrote it!
Hassan Abdelazeem
Hassan Abdelazeem el 8 de Sept. de 2020
OK, I am so sorry about that now, it is working in a good manner , I appraciate your effort , thank you indded
Regards
Star Strider
Star Strider el 8 de Sept. de 2020
As always, my pleasure!

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