Mean of a field of a struct

As seen in image below, I have a struct of 5 fields. I need to compute the avarege of the HV3, HV5, HV7 and thd in 1st row, then in the second row and so on seperately.. Have a nice weekend..

Answer 1

[Matt J]

C=struct2cell(rmfield(S,'name'));

A=cell2mat(reshape(C,1,4,[]));

Averages = reshape( mean(A,1),4,[]).'

[FG]

I cant remove names because parameters are shown on the names..

[Matt J]

[array2table({S.name}.'),array2table(Averages)]

[FG]

Thanks Matt..

Answer 2

[Ameer Hamza]

Try something like this

S_new = rmfield(S, 'name');
S_out = arrayfun(@(s) structfun(@mean, s, 'uni', 0), S_new);
[S_out.name] = S.name;

[FG]

Sorry could'nt understand it.. Just tell me how I can mean the HV3 in the first row

[Ameer Hamza]

Is there any error?

You can get that mean using

mean(S(1).HV3)

[FG]

Thank you.. Quite OK

[FG]

Ave3=mean(M3, k) ----> what does k mean here ?

If M3=([S(i) .HV3]) and how can I get the mean of M3 between 1660-98700 time interval ?

[FG]

Infact the script is;

-----------------

for i=1:length(S);

M3=([S(i) .HV3]);

M5=([S(i) .HV5]);

M7=([S(i) .HV7]);

Mthd=([S(i) .thd])

for k=1:length(S);

Ave3=mean(M3, k) ;

Ave5=mean(M5, k);

Ave7=mean(M7, k);

Avethd=mean(Mthd, k);

end

end

[Ameer Hamza]

k here denotes the dimension along which to average. This is not the correct option to use for your case. To average a specific number of elements, try something like this

Ave3 = zeros(size(S));
Ave5 = zeros(size(S));
Ave7 = zeros(size(S));
Avethd = zeros(size(S));
for i=1:length(S)
    M3=([S(i).HV3]);
    M5=([S(i).HV5]);
    M7=([S(i).HV7]);
    Mthd = ([S(i).thd]);
    
    Ave3(i)=mean(M3(1660:9870)) ;
    Ave5(i)=mean(M5(1660:9870));
    Ave7(i)=mean(M7(1660:9870));
    Avethd(i)=mean(Mthd(1660:9870));
end

This code also store average values for all the iterations.

[FG]

Thank you Ameer.. I just need to write it to excel, job's done !

[Ameer Hamza]

I am glad to be of help!