Replacing several values in multidimensional array simultaneously

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I have a multidimensional array, e.g.
A(:,:,1) = [1 2 3 ; 4 5 6];
A(:,:,2) = [7 8 9 ; 10 11 12];
I want to replace several of the values in this array with the same value simultaneously. Specifically I want to do this column-wise, the result should be e.g.
A(:,2,1) = [-1 ; -2];
A(:,3,2) = [-1 ; -2];
yielding
A(:,:,1) = [1 -1 3 ; 4 5 -1];
A(:,:,2) = [7 -2 9 ; 10 11 -2];
I attempted this by
B = [2 3]; C = [1 2];
A(:,B,C) = [-1 ; -2];
but it does not give the wanted result.
Any idea on how to do this without performing a for-loop?

Respuesta aceptada

Bruno Luong
Bruno Luong el 14 de Sept. de 2020
Editada: Bruno Luong el 14 de Sept. de 2020
A(:,:,1) = [1 2 3 ; 4 5 6];
A(:,:,2) = [7 8 9 ; 10 11 12];
s = size(A);
A(:, sub2ind(s(2:3),[2 3],[1 2])) = 0 % = [0 0; 0 0]
  2 comentarios
David Hoffmeyer
David Hoffmeyer el 14 de Sept. de 2020
Editada: David Hoffmeyer el 14 de Sept. de 2020
Thanks for your input. However, I have not been precise enough in my question. I need to replace a number of columns in the array with a column containing non-identical values (see the edited question), and not just 0. In that case your proposal does not work. Can you alter it correspondingly?
Bruno Luong
Bruno Luong el 14 de Sept. de 2020
Editada: Bruno Luong el 14 de Sept. de 2020
Just replace the RHS as I hint in my answer with "% = [0 0; 0 0]"
A(:, sub2ind(s(2:3),[2 3],[1 2])) = [[-1;-2], [-1;-2]]

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