boxplot with vectors of different lengths
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Hi MATLAB folks,
I am wondering how I can boxplot two column matrices with different lengths, e.g.
c_1=rand(1,20);
c_2=rand(1,100);
how I can do
boxplot(C);
where:
C=cell(1,2);
C{1}=c_1(:);
C{2}=c_2(:);
Is there any solution to that?
Many thanks in advance, -V
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Más respuestas (2)
Matt Raum
el 23 de Mzo. de 2017
I ran into the same issue -- here's a quick re-wrapping of boxplot that can be called on a cell array containing vectors of variable size:
col=@(x)reshape(x,numel(x),1);
boxplot2=@(C,varargin)boxplot(cell2mat(cellfun(col,col(C),'uni',0)),cell2mat(arrayfun(@(I)I*ones(numel(C{I}),1),col(1:numel(C)),'uni',0)),varargin{:});
boxplot2 automatically generates the necessary grouping array. All you need to pass to it is a cell array of the vectors you want box plotted.
boxplot2({randn(1,100),10+2*randn(200,1)});
4 comentarios
Alexandre Soares da Silva
el 28 de Abr. de 2017
Thank you so much for that wrapper. Saved my statistics homework ;)
Francesco Giuseppe Augello
el 23 de Mzo. de 2021
thank you man, it was super useful
Aihong CUI
el 29 de Nov. de 2022
very useful, thank you very much
Joris Bockhofer
el 5 de Jul. de 2023
Editada: Joris Bockhofer
el 5 de Jul. de 2023
You are a hero. The hero MatLab doesnt deserve....
I want to add that this will be a problem when trying to identify boxes belonging to a certain group.
To "fix" this create an array of strings that map the number of the, now numbered boxes to a legend label and add a legend in a hacky way :)
legendStrArray = string();
for i = 1:numBoxes
legendStrArray(1,end+1) = string(i) + " = " + yourListOfGroupLabels(i); %
end
legendStrArray = legendStrArray(1,2:end);
hLegend = legend(findall(gca,'Tag','Box'), legendStrArray); % finds a figure with the tag box which should be your boxplot
Joey Porter
el 21 de Abr. de 2020
5 votos
This is my first feedback so please forgive if I've misunderstood but I solved this issue with a simpler explanation (at least for me).
boxplot plots each columns as a separate variable (box) as long as the lengths of each column are the same.
I simply created a NaN matrix with number of rows equal to the length of my longest variable, then populated with my variable data. The NaNs are not plotted on the box plot but allows variables of unequal length to be plotted. Also to add more variables, simply increase the number of columns in your NaN array.
I hope this helps anyone returning to this thread :)
3 comentarios
Adam Danz
el 21 de Abr. de 2020
That's another good approach.
You can also use padarray() to pad the cell elements with NaN values.
% Create 1x3 cell array of vectors with different lengths
C = {rand(20,1), rand(15,1), rand(200,1)};
% Pad each vector with NaN values to equate lengths
maxNumEl = max(cellfun(@numel,C));
Cpad = cellfun(@(x){padarray(x(:),[maxNumEl-numel(x),0],NaN,'post')}, C);
% Convert cell array to matrix and run boxplot
Cmat = cell2mat(Cpad);
boxplot(Cmat)
Joey Porter
el 21 de Abr. de 2020
Thanks Adam.
I didn't know there was a function for padding. I'll use this next time!
Camilo Cárdenas
el 29 de Abr. de 2022
Gracias! excelente dato!
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