The number of rows in A must be the same as the number of elements of b.
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Ricardo López
el 19 de Oct. de 2020
Respondida: Walter Roberson
el 20 de Oct. de 2020
%% Discrete modelling
Ae=(1-(K*ts)/Cth);
Be=(ts*COP*HP)/Cth;
D=ts*K/Cth;
Tin=zeros(1,i);
u=zeros(1,i);
for j=1:i
% f=@(u) sum(u(j)*gamma(j));
f=u(j);
%%%Starting point%%%
u0=0;
if j>1
Tin(j+1)=Ae*Tin(j)+Be*u(j)+D*Tout(j);
else
Tin(j)=0;
end
%%%Constraints%%%
%%%Equality%%%%
Aeq=Be;
beq=(Tin(j+1)-Ae*Tin(j)-D*Tout(j));
%%%Inequality%%%
A=[(Tin(j)*Be)/(Tin(j+1)-Ae*Tin(j)-D*Tout(j)) ;(-(Tin(j)*Be)/(Tin(j+1)-Ae*Tin(j)-D*Tout(j)))];
b=[Tmax ; -Tmin];
options = optimoptions(@linprog,'Display', 'off');
u(j)=linprog(f,u0,A,b,Aeq,beq,umin,umax,options);
end
I am getting the error: The number of rows in A must be the same as the number of elements of b.
Does anyone know why?
Thanks!
4 comentarios
Walter Roberson
el 20 de Oct. de 2020
We cannot tell. There are too many variables that you do not show us the size of.
Look at size(A) and size(b) and look at the size of the variables used to construct A and b
Respuesta aceptada
Walter Roberson
el 20 de Oct. de 2020
MATLAB function calls use positional parameters, not named parameters. The second parameter you are passing, u0, is getting received in the slot where the linear constraints matrix is expected, so you are setting your constraints matrix to scalar 0. Your variable named A is being received in the linear constraints outcome vector, and has two elements, which is not the same as the number of rows of your scalar u0.
Your u0 parameter should not be present.
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