How t generate cone using scattered random point cloud?

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M.S. Khan
M.S. Khan el 20 de Oct. de 2020
Comentada: anuradha verma el 11 de Nov. de 2022
Using the below code, i have geneated sphere. could anyone please guide me how to geneate cone using random scattered point cloud.
I will be very thankful. Thanks in advance to all community members for their cooperation and guidance. Regards
r = randn (10000,3);
r = round(bsxfun(@rdivide,r,sqrt(sum(r.^2,2)))*130);
x = r(:,1);
y = r(:,2);
z = r(:,3);
scatter3(x,y,z)
  3 comentarios
M.S. Khan
M.S. Khan el 20 de Oct. de 2020
Dear KSSV, thanks for your kind reply. This code provides cone also but not random scattered point cloud. Regards
M.S. Khan
M.S. Khan el 20 de Oct. de 2020
They are using grid that means its uniform spaced points? Could you guide me how to generate cone using scattered random point cloud.

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Respuesta aceptada

Bruno Luong
Bruno Luong el 20 de Oct. de 2020
Editada: Bruno Luong el 20 de Oct. de 2020
This code provides the uniform distribution on the surface of the cone
h = 3; % height
r = 1; % base radius
n = 1e4; % number of points
topcapflag = true; % include the top cap or not
rho = sqrt(rand(1,n));
z = h*rho;
if topcapflag
z(rand(1,n)<r/(h+r))=h;
end
theta = (2*pi)*rand(1,n);
rho = r*rho;
x = cos(theta).*rho;
y = sin(theta).*rho;
% graphic check
figure
plot3(x,y,z,'.')
axis equal

Más respuestas (1)

Ameer Hamza
Ameer Hamza el 20 de Oct. de 2020
This is one way. The distribution is non-uniform
h = 2; % height of cone
r = 1; % maximum radius of cross section of the cone
n = 10000;
z = rand(1, n)*h;
t = rand(1, n)*2*pi;
r = interp1([0 h], [0 r], z);
[x, y] = pol2cart(t, r);
scatter3(x, y, z)
  23 comentarios
Bruno Luong
Bruno Luong el 10 de Nov. de 2022
Editada: Bruno Luong el 10 de Nov. de 2022
@anuradha verma, it's not difficult, if you have new question, just click on Ask, or this link:https://mathworks.com/matlabcentral/answers/questions/new
then describe the problem accurately,.
This thread is opened by the author for his problem and it's has been answered.
You question merits a new thread

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